A particle is represented at time
by the wavefunction, ![Rendered by QuickLaTeX.com \[\psi(x,0)=\left{\begin{array}{cl} A(a^2-x^2),&-a\leq x \leq a\ \\0,& \mbox{otherwise}\end{array}\right.\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-018369b7d13d8fac687bce37af99e1ed_l3.png)
Where A and a are positive real constants. The normalization constant A is: ![Rendered by QuickLaTeX.com \[A. ~~\sqrt{\frac{16}{15a^5}} ~~~B. ~~\sqrt{\frac{15}{16a^4}} ~~~C. ~~\sqrt{\frac{15}{16a^5}} ~~~D. ~~\sqrt{\frac{16}{15a^4}}\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-5af793486af8bfe2ce74b28c000e11bf_l3.png)
![Rendered by QuickLaTeX.com \[\psi(x,0)=\left{\begin{array}{cl} A(a^2-x^2),&-a\leq x \leq a\ \\0,& \mbox{otherwise}\end{array}\right.\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-018369b7d13d8fac687bce37af99e1ed_l3.png)
![Rendered by QuickLaTeX.com \[A. ~~\sqrt{\frac{16}{15a^5}} ~~~B. ~~\sqrt{\frac{15}{16a^4}} ~~~C. ~~\sqrt{\frac{15}{16a^5}} ~~~D. ~~\sqrt{\frac{16}{15a^4}}\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-5af793486af8bfe2ce74b28c000e11bf_l3.png)
The correct choice is C. Watch the following video for complete solution: