A particle is represented at time
by the wavefunction, ![Rendered by QuickLaTeX.com \[\psi(x,0)=\left{\begin{array}{cl} A(a^2-x^2),&-a\leq x \leq a\ \\0,& \mbox{otherwise}\end{array}\right.\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-018369b7d13d8fac687bce37af99e1ed_l3.png)
Where A and a are positive real constants. The normalization constant A is: ![Rendered by QuickLaTeX.com \[A. ~~\sqrt{\frac{16}{15a^5}} ~~~B. ~~\sqrt{\frac{15}{16a^4}} ~~~C. ~~\sqrt{\frac{15}{16a^5}} ~~~D. ~~\sqrt{\frac{16}{15a^4}}\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-5af793486af8bfe2ce74b28c000e11bf_l3.png)
![Rendered by QuickLaTeX.com \[\psi(x,0)=\left{\begin{array}{cl} A(a^2-x^2),&-a\leq x \leq a\ \\0,& \mbox{otherwise}\end{array}\right.\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-018369b7d13d8fac687bce37af99e1ed_l3.png)
![Rendered by QuickLaTeX.com \[A. ~~\sqrt{\frac{16}{15a^5}} ~~~B. ~~\sqrt{\frac{15}{16a^4}} ~~~C. ~~\sqrt{\frac{15}{16a^5}} ~~~D. ~~\sqrt{\frac{16}{15a^4}}\]](https://physicshut.com/wp-content/ql-cache/quicklatex.com-5af793486af8bfe2ce74b28c000e11bf_l3.png)
The correct choice is C. Watch the following video for complete solution:
The correct choice is C. Watch the following video for complete solution:
The correct choices are A, C and D Watch the following video for full solution:
The non-zero commutator brackets are: A. B.
C.
D.
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Keywords: IIT Bombay, Quantum Mechanics-I, Prof. P. Ramadevi, Chandigarh University, NPTEL Assignment-1, Numerical-5
If you are interested to know more about scalar and vector fields, then watch video lecture by me on this topic at the following link: https://youtu.be/H4eWdwaGWYI. Another video, that may be of interest to the reader of this post is ‘Transverse nature of electromagnetic waves’. The link to this video lecture by me is given
Gradient of a Scalar Field Read More »